Formulas (turquoise)
Acronym |
Terminology/Phrase |
Formula(s) |
Real Meaning /Reference |
EV or BCWP |
Earned Value or Budgeted[1] Cost of the Work Performed |
EV = %completed * BAC |
· How much work was actually done as described in the budget · A method for measuring project performance. It compares the amount of work planned with what was actually accomplished to determine if cost and schedule performance is as planned. Earned Value (EV), is a percentage of the total budget equal to the work actually performed. |
PV or BCWS |
Planned Value or Budget Cost of Work Scheduled |
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· How Much work should be done (The estimated value of the planned work) · The budget that is part of the approved cost estimate planned to be spent on the activity during a given period |
AC or ACWP |
Actual Cost or Actual Cost of the Work Performed |
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· What is the actual cost incurred? · What have we spent to date? · The actual cost that is the total of direct and indirect costs incurred in accomplishing work on the activity during the given period |
BAC |
Budget At Completion |
Budget at completion |
· How much did you budget for the job? The total budget. |
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Variance |
Variance = BAC – AC |
· Planned – actual (i.e. planned was three weeks, actual was two weeks – resulting in a one week variance) |
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Percentage complete |
%complete = EV/BAC |
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CV |
Cost Variance |
CV = EV – AC
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· Any difference between the estimated cost of an activity and the actual cost of that activity |
SV |
Schedule Variance |
SV = EV – PV |
· Any difference between the scheduled completion of an activity and the actual completion of that activity |
CPI |
Cost Performance Index |
CPI = EV/AC[2] CPI <1 means over budget CPI >1 cost are below budget CPI equal to 1 means costs equal benefits |
· Used to forecast project cost at completion · The ratio of budget cost to actual costs.
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SPI |
Schedule Performance Index |
SPI = EV/PV
SPI <1 project will be late SPI > 1`project is ahead of schedule SPI equal to 1 means costs equal means project is on scheule |
· Used to forecast project completion date · The SPI is used in some application areas to forecast the project completion date.
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Cumulative CPI |
Sum of all individual EV divided by the sum of all individual AC |
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Critical Ratio |
SPI * CPI |
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Critical Path uncertainty |
The Critical Path uncertainty = the sum of the (square root of the variances) |
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EAC |
Estimate At Completion |
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Several possible calculations depending upon the status of the project |
EAC |
Estimate At Completion |
EAC = BAC / CPI |
· Used if no variances from BAC or you will continue at the same rate of spending. · Most commonly used on PMP exams |
EAC |
Estimate At Completion |
EAC=AC+ETC |
· Used when original estimate is flawed · Actual plus new estimate for remaining work. |
EAC |
Estimate At Completion |
EAC=AC + (BAC –EV) |
· Used when current variances are atypical of the future. · Actual to date plus remaining budget. |
EAC |
Estimate At Completion |
EAC=(AC + (BAC -EV))/CPI . |
· Used when variances are thought to be typical of the future · Actual to date plus remaining budget modified by performance |
ETC |
Estimate To Completion |
ETC = EAC – AC |
· How much will the project cost |
VAC |
Variance At Completion |
VAC = BAC – EAC |
· How much over budget will we be at ten end of the project? |
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Slack |
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(LS-ES) or (LF-EF) |
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ES |
Early Start |
EF – duration + 1 |
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EF |
Early Finish |
ES + duration – 1 |
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LS |
Late Start |
LF – duration + 1 |
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LF |
Late Finish |
LS + duration -1 |
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FF |
Free Float |
ES (of successor) – EF (of current task) – 1 |
· amount of time the current activity can be delayed without delaying the early start of the successor task |
TF |
Total Float |
LF – EF (of current task) |
· amount of time the current activity can be delayed without delaying the LF of the entire project. |
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Budget Burn Rate (linear) |
BAC / planned duration |
· Example ($1,000 / 4 weeks = $250 per week) |
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Actual Burn Rate (linear) |
AC / Actual duration |
· Example ($1,200 / 5 weeks = $240 per week) |
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Excepted Value |
Probability (%) * consequences |
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Simple Interest
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Interest = Principle X Rate x Time |
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EMV |
Expected Monetary Value
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EMV = Odds of occurrence x amount at stake
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Present Value |
Present Value = FV/(1+r)n |
FV = Future Value r = Interest Rate n = # of periods |
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Future Value |
FV = PV x (1 + i)
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n = Number of time periods (years) PV = Present value (of money) i = interest rate
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Pay back |
Pay back = period of time to recover investment through cash flow |
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BCR |
Benefits Cost Ratio |
BCR greater than 1 is good BCR less than 1 is bad BCR equal to 1 means costs equal benefits |
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Opportunity cost |
No calculation |
· Defines the opportunity given up by selecting one project over another |
IRR |
Internal Rate of Return |
Complex calculations requiring computer |
· If a company has more than one project to invest, the company may look at projects’ return and then select the highest one. |
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Fixed Cost |
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· Resource constrained scheduling, end date may vary |
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Fixed Time |
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· Resource variable scheduling, end date fixed |
NPV |
Net Present Value |
To calculate you need to calculate the present value of both income and revenue figures and then add up the present values |
· The present value of the total benefits (income or revenue) less the costs. |
Valuable Hint NOT Written in Project Management Books About Costs
(Or more succinctly “How to know you’re in trouble”)
When EV (BWCP) is used in an equation, it always goes first:
CV = EV – AC
If you get a negative number, your project is over budget.
SV = EV – PV
Again, if you get a negative number, your project will overrun its schedule.
Communication channels (assuming a binary distribution)
N (N-1) / 2
Program Evaluation and Review Technique (PERT)
Other Notes
PERT assumes a beta distribution
Weighting – Pessimistic = 1, Most likely = 2 and Optimistic =3
Standard Deviation
(P-O)/6
Task Variance
[ (P-O) / 6]
Project Variance
Project Variance = Take the square root of the sum of the task variances
Conventional Critical Path Methodology
A to B |
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Finish to Start (FS) |
zero delay |
Start to Start (SS) |
implies delay on B after Start of A |
Finish to Finish |
A must finish before B |
Start to Finish |
A must start before B can finish |
Measures of Central Tendency (Mean, Median, Mode)
Mean
The mean is the sum of the measures divided by the number of measurements
Mode
The mode is the most frequent occurring observation in the data under consideration.
If the observation has two modes, then the data is said to be bi-modal distribution.
If the observations have three or more modes, then the mode is no longer a viable measure of central tendancy.
2,2,2,3,3,5,7,10,12
mode = 2
Measures of Variability
Range
The range is the difference between the largest measure and the smallest measurement.
The range does not use all available observations. It uses only the two extreme values. It will have the same dimension, or unit of measure as the original data.
Standard Deviation
The standard deviation is the positive square root of the variance.
Normal Distribution
= 68.26
= 94.36
= 99.73
= 99.99
Note 68.26/2 = 34.13 which is 50% above the one sigma mean and 50% below one sigma mena.
Other
· UCL / LCL Upper Control Lime & Lower Control Limit on a control chart
· Pareto: 80% of problems come from 20% of the work
· Crashing: Slope = Crash Cost – Normal Cost/Crash Time – Normal Time
· Progress Reporting: 0/100; 50/50; 20/80
· Standard Deviation of a project = Square Root of Sum of Critical Path Variances
· Slack = LST – EST (Latest Start Time – Earliest Start Time)
= LFT – EFT (Latest Finish Time – Earliest Finish Time)
Histogram |
Variance & Standard Deviation |
Add up your number of observations. (N) |
Find the mean (x-bar) |
Determine the Range (R) |
Subtract the mean from every observation (n) |
Determine Classes (K) |
Square each result |
Determine Class Width (H) where H = R/K |
Add up all the squares |
Construct Frequency table |
Divide that number by n-1 (for the sample) or N (for the population) This is the Variance |
Plot Data |
Square root the answer This is the Standard Deviation |
Binomial Distribution (Success or Failure)
· A coin will be tossed 5 times but the coin is biased so that the probability of heads for each toss is 0.04. Heads is success, tails is failure.
· N = number of items in the sample (the number of coin tosses)
· X = number of items for which the probability is desired (number of Heads)
· In Appendix A we go to column N and find where N = 5
· In Appendix A we go to where p = 0.40
· Each row represents the probability of 0, 1,2, 3, 4, and 5 successes
· Add them up
Poisson Distribution
· A light bulb manufacturer has a known defective rate of 4%. From a sample of 40, the probability of 4 or more defective light
· µ = np = (40) (.04) = 1.6
· Probability of 4 or more defective is = 1 – probability of 3 or less defective
· In the table, find where µ = 1.6
· Add up the numbers where x has a value of 0, 1, 2, or 3 (this is the P of 3 or less defectives)
· Subtract that number from 1.0
· Find np (sample x defective rate)
· Calculate up to by going to the table, finding np, adding it up
· Subtract that answer from 1 to x or greater probability
Normal Distribution (also known as Gaussian)
· If process produces parts with mean of _ and standard Deviation of _, what is the P that one random part has a measurement of _?
· Mean time of a bank transaction is 5.25 with a standard deviation of 0.75 minutes and the values are normally distributed. What is the probability that a transaction will occur between 4.0 and 5.25 minutes and below 4.0?
· Z = 4.0 – 5.25/ 0.75 = -1.67
· Go to Appendix A and find 1.67 = 0.4525
· Because we know that µ is 5.25, the probability that a transaction will take less than 5.25 is .05 (1/2)
· Therefore, the probability that a transaction will be less than 4 minutes = 0.5 – 0.4525 = 0.0475
Sampling Distributions (number of standard Deviations that a sample mean is away from the population mean)
· If normal distribution with mean of _ and SD of _. From sample of _ what is P that the sample mean is >, <, =, or between _?
· Hospital emergency room where it has a record waiting time of 30 minutes with a standard deviation of 5 minutes. If a sample of 35 is measured, what is the probability that the sample mean would be greater than 31.5 minutes?
· Do the Z calculation to get 1.77
· Find 1.77 in Appendix A (go to 1.7 and then across to 0.07)
· Subtract that probability from the .5 probability = .50 – .4616 = .0384
· This tells us that there is only a .0384 probability that, from the sample of 35, the sample mean will be greater than 31.5.
Measure of shapes (skewness)
Symmetrical (Bell sphere)
Positive skew (shift to right)
Negative skew (shift to left)
Beta Distribution = skewed in one direction